x^2-3.005x+0.005=0

Solution for x^2-3.005x+0.005=0 equation:

x^2-3.005x+0.005=0

a = 1; b = -3.005; c = +0.005;
Δ = b2-4ac
Δ = -3.0052-4·1·0.005
Δ = 9.010025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.005)-\sqrt{9.010025}}{2*1}=\frac{3.005-\sqrt{9.010025}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.005)+\sqrt{9.010025}}{2*1}=\frac{3.005+\sqrt{9.010025}}{2}
$